Tutorial
Electrochemistry
1.
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Given below are the
std reduction potentials of silver ion and iron (II) ions.
Ag+(aq) +
e ®
Ag(s) E° = +0.80 V
Fe2+(aq) +
2e ®
Fe(s) E° = -0.44 V
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2.
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Given
the following standard reduction potentials
Zn2+(aq) +
2e ®
Zn(s) E° = - 0.76 V
Fe3+(aq) +
e ®
Fe2+(aq) E° = +0.77 V
Will
Zn reduced Fe3+ ion to Fe2+ ions?
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3.
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Given
2 half – equations
Ni2+(aq) +
2e ⇌ Ni(s) E°
= -0.25 V
Cr3+(aq) +
3e ⇌ Cr(s) E°
= -0.74 V
Calculate the cell potential when [Ni2+]
= 1x10-3 M and [Cr3+] = 2.0 x 10-3 M
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4.
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Determine
the anode and cathode and write the half cell reaction for the following electrochemical
cell.
Cu(s) +
2Ag+(aq) ®
Cu2+(aq) + 2Ag(s)
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5.
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Write the cell
diagram for the following voltaic cell
2
Ag+(aq) + Cd(s)
®
Cd2+(aq) + 2 Ag(s)
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6.
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Calculate E°cell of the following electrochemical cell and determine
whether the reaction is spontaneous or non spontaneous
Br2(g) +
2LiF(aq) ®
F2(g) + 2LiBr(aq)
Given:
E° Li+/Li = -3.03 V ; E°Br2/Br-
= +1.07 V ; E° F2/F- = +2.87 V
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salam, pn soalan no 6 tu cam ne nak tau element yang mane satu nak guna. yang mane nak tolaka yang mane nak cari E cell
ReplyDelete1)E cell= E (r)- E(O) dalam handout atau 2) E cell = E(r)+E(O) dalam buku.....mana satu yang betul?
ReplyDeleteSyabas Pn Rozainita! Penggunaan laman blog sebagai e-modul kepada pelajar-pelajar memang satu usaha yang baik. Teruskan usaha puan...
ReplyDeleteHj. Zuls
Terima kasih Tn Hj. Zulkifli
Delete:)